11[5-(4-2x)]+10x=4(8x+4)-5

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Solution for 11[5-(4-2x)]+10x=4(8x+4)-5 equation:


Simplifying
11[5 + -1(4 + -2x)] + 10x = 4(8x + 4) + -5
11[5 + (4 * -1 + -2x * -1)] + 10x = 4(8x + 4) + -5
11[5 + (-4 + 2x)] + 10x = 4(8x + 4) + -5

Combine like terms: 5 + -4 = 1
11[1 + 2x] + 10x = 4(8x + 4) + -5
[1 * 11 + 2x * 11] + 10x = 4(8x + 4) + -5
[11 + 22x] + 10x = 4(8x + 4) + -5

Combine like terms: 22x + 10x = 32x
11 + 32x = 4(8x + 4) + -5

Reorder the terms:
11 + 32x = 4(4 + 8x) + -5
11 + 32x = (4 * 4 + 8x * 4) + -5
11 + 32x = (16 + 32x) + -5

Reorder the terms:
11 + 32x = 16 + -5 + 32x

Combine like terms: 16 + -5 = 11
11 + 32x = 11 + 32x

Add '-11' to each side of the equation.
11 + -11 + 32x = 11 + -11 + 32x

Combine like terms: 11 + -11 = 0
0 + 32x = 11 + -11 + 32x
32x = 11 + -11 + 32x

Combine like terms: 11 + -11 = 0
32x = 0 + 32x
32x = 32x

Add '-32x' to each side of the equation.
32x + -32x = 32x + -32x

Combine like terms: 32x + -32x = 0
0 = 32x + -32x

Combine like terms: 32x + -32x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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